stackoverflow June 21, 2026 Rep: 1,264

Why `decltype(x)` in a lambda evaluates to reference even though the `x` is capture by value

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June 21, 2026 Score: 2 Rep: 105,264 Quality: Low Completeness: 40%

As you might know, decltype(...) has custom behavior when given a variable name (as opposed to any other expression).

As a part of that, decltype(x) doesn't refer to the capture. It refers to int &x in main().

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