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python python-asyncio

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Accepted Answer
July 7, 2026 Score: 1 Rep: 82 Quality: High Completeness: 60%

An asyncio task does not become inactive if handled exceptions are caught correctly. If a worker stops updating, it is typically blocked on an await, cancelled, or terminated by an uncaught exception. You can check whether a task is still running with task.done() and task.cancelled(), and use timeouts plus supervision for reliable long-running workers.

tasks = {
    i: asyncio.create_task(worker(i))
    for i in range(3)
}
for i, task in tasks.items():
    print(
        f"Worker {i}: "
        f"done={task.done()}, "
        f"cancelled={task.cancelled()}"
    )

To prevent workers from hanging indefinitely, wrap long-running operations with a timeout:

async with asyncio.timeout(30):
    data = await api.fetch()

Also, let task cancellation propagate:

try:
    ...
except ConnectionError:
    ...
except asyncio.CancelledError:
    raise

This pattern helps ensure workers remain responsive and recover from temporary failures.

July 7, 2026 Score: 2 Rep: 77 Quality: Low Completeness: 60%

In my experience, a handled exception will not stop an asyncio task. If the exception is caught inside the coroutine, the while True loop should continue.

If the worker stops updating, check these cases:

1. The task actually crashed

An exception outside your try/except will terminate the task:

task.done()
task.exception()

Use:

except Exception:
    logger.exception("Worker failed")

to see hidden errors.

2. The task is blocked

Common causes:

requests.get(url)   # blocks event loop

Use async libraries or:

await asyncio.tothread(requests.get, url)

3. An async operation never returns

Add timeouts:

await asyncio.waitfor(api_call(), timeout=10)

4. Shared state updates need protection

For complex updates:

async with lock:
    cache.update(data)

A worker that catches its own exceptions does not silently die. The problem is usually an uncaught exception, blocking code, an infinite wait, or a synchronization issue.